Answer:
(a) f= 622.79 Hz
(b) f= 578.82 Hz
Explanation:
Given Data
Frequency= 600 Hz
Distance=1.0 m
n=120 rpm
Temperature =20 degree
Before solve this problem we need to find The sound generator moves on a circular with tangential velocity
So
Speed of sound is given by
c = √(γ·R·T/M)
............in an ideal gas
where γ heat capacity ratio
R universal gas constant
T absolute temperature
M molar mass
The speed of sound at 20°C is
c = √(1.40 ×8.314472J/molK ×293.15K / 0.0289645kg/mol)
c= 343.24m/s
The sound moves on a circular with tangential velocity
vt = ω·r.................where
ω=2·π·n
vt= 2·π·n·r
vt= 2·π · 120min⁻¹ · 1m
vt= 753.6 m/min
convert m/min to m/sec
vt= 12.56 m/s
Part A
For maximum frequency is observed
v = vt
f = f₀/(1 - vt/c )
f= 600Hz / (1 - (12.56m/s / 343.24m/s) )
f= 622.789 Hz
Part B
For minimum frequency is observed
v = -vt
f = f₀/(1 + vt/c )
f= 600Hz / (1 + (12.56m/s / 343.24m/s) )
f= 578.82 Hz
0.234m !!!!!! hope this helps :)))
Answer:
Coefficient of friction is 
.
Work done is 
.
Explanation:
Given:
Mass of the box (
): 
kg
Force needed (
): 
N
The formula to calculate the coefficient of friction between the floor and the box is given by
Here, 
is the coefficient of friction and 
is the acceleration due to gravity.
Substitute N for , kg for and 
m/s² for into equation (1) and solve to calculate the value of the coefficient of friction.
The formula to calculate the work done in overcoming the friction is given by
Here, 
is the work done and 
is the distance travelled.
Substitute N for and 
for into equation (2) to calculate the work done.
We dont have the powerpoint
