Number 1 is incorrect, the genotypes are given to you. You need to use GG and gg. The outcome would be 100% Gg.
Number 2 is incorrect, the genotypes are given to you. You need to use Gg and Gg. The outcome would be 25% gg, 25% GG, and 50% Gg.
Number 3 is incorrect, the genotypes are given to you. You need to use TT and tt. The outcome would be 100% Tt.
Number 4 is incorrect, the genotypes are given to you. You need to use RR and rr. The outcome would be 100% Rr.
Please read the directions and use the genotypes they give you! The information is all there for you, you just need to put it in correctly. If you're still having trouble understanding how to do this, feel free to message me and I'd be happy to help you.
Answer:
C) 0.121 M
Explanation:
HCl + H₂O = H₃O⁺ + OH⁻
.121M .121M
HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .
So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.
well none its made from iron nut i would go with c. a solution sorry if im wrong tell me in comments
Given the solubility of strontium arsenate is 0.0480 g/l . we have to convert it into mol/L by dividing it over molar mass (540.7 g/mol)
Molar solubility = 0.0480 / 540.7 = 8.9 x 10⁻⁵ mol/L
Dissociation equation:
Sr₃(AsO₄)₂(s) → 3 Sr²⁺(aq) + 2 AsO₄³⁻(aq)
3 s 2 s
Ksp = [Sr²⁺]³ [AsO₄³⁻]²
= (3s)³ (2s)²
= 108 s⁵
Ksp = 108 (8.9 x 10⁻⁵) = 5.95 x 10⁻¹⁹
Lets find the electronegativity difference between the bonded atoms;
C-H = 2.6-2.2 = 0.4
C-F = 4.0-2.6 = 1.4
F-F = 4.0-4.0 = 0
H-O = 3.4-2.2 = 1.2
Here the electronegativity difference is highest for C-F bond hence C-F bond is most polar.