Answer:
41 years old.
Step-by-step explanation:
Let x represent age of younger child.
We have been given that a mother has two children whose ages differ by 5 years. So the age of older child would be .
The sum of the squares of their ages is 97. We can represent this information in an equation as:
Let us solve for x.
Divide both sides by 2:
Since age cannot be negative, therefore, age of younger child is 4 years.
Age of older child would be
Therefore, the age of older child would be 9 years.
We have been given that the square of the mother's age can be found by writing the squares of the children's ages one after the other as a four-digit number.
Square of 4:
Square of 9: .
Square of mother's age:
To find mother's age, we need to take positive square root of 1681 as:
Therefore, the mother is 41 years old.
Approximate <em>R'</em> by using a linear approximation: for <em>x</em> close enough to 24, you have
<em>R'(x)</em> ≈ <em>L(x)</em> = <em>R' </em>(20) + <em>R''</em> (20) (<em>x</em> - 20)
Then
<em>R'</em> (24) ≈ <em>R'</em> (20) + <em>R''</em> (20) (24 - 20) = -4 + 50 (24 - 20) = 196
well there is 7x4, 14x2, and 28x1 of course.