How many moles of Hions are present in the following aqueous solution?

Chemistry

1 answer:

Fittoniya [83]2 years ago

6 0

Answer:

Nitric acid is a strong acid meaning it completely dissociates in water. Therefore, you can say that the concentration of H+ ions in solution is the same as the concentration of the acid (molar concentration). So once you have that, you can use the pH formula to find the pH of the acid.

pH = -log[H+]

So if you have .15 M HNO3 the pH is 0.82.

But, if you have a different concentration, the pH will change.

Explanation:

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What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.

AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

$pH=pK_{a} + log(\frac{[Base]}{[Acid]})$

According to the given conditions, the equation will become as follow

$pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})$

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

$pH=6.86 + log(\frac{0.058}{0.042})$