Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have
Height of shuttle at that instant = AC = 1.17 miles
3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w
Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)
Hope this helps.
Answer:
your answer is C.
Step-by-step explanation: