Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
Answer:
Step-by-step explanation:
<u><em>The options of the question are</em></u>
2(x − 1)2 = 4
2(x − 1)2 = −4
2(x − 2)2 = 4
2(x − 2)2 = −4
we have
This is a vertical parabola open upward
The vertex represent the minimum value
The quadratic equation in vertex form is
where
a is a coefficient
(h,k) is the vertex
so
Convert the quadratic equation in vertex form
Factor 2 leading coefficient
Complete the squares
Rewrite as perfect squares
The vertex is the point (1,-4)
Move the constant to the right side
Answer:
Not quite sure what the purpose of this question is, but... How do you get straight A's?
Use a ruler
*insert rimshot*
Step-by-step explanation:
Answer:
A) 1178
Step-by-step explanation:
height is 15
radius is 5
diameter is 10
π * 5^2 * 15= 1178
Your equation is already in one of the standard form. Specifically, the slope intercept form.
y=mx + b.
m is the slope, b is the intercept.
Start with the intercept y= 2, the point (0,2).
A slope of 3 would give you (1,5) as a second point for your line.
Get a ruler and draw a line through the two points.
