The quotient is x^3 + 4x^2 -x + 1.
Solution:
By polynomial grid division, we start by the divisor 3x + 10 placed on the column headings.
3x 10
x^3 3x^4
We know that 3x^4 must be in the top left which means that the first row entry must be x^3. So the row and column multiply to 3x^4. We use this to fill in all of the first row, multiplying x^3 by the terms of the column entries.
3x 10
x^3 3x^4 10x^3
4x^2
We now got 10x^3 though we want 22x^3. The next cubic entry must then be 12x^3 so that the overall sum is 22x^3.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3
Now we have 40x^2, so the next quadratic entry must be -3x^2 so that the overall sum is 37x^2.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
This time we have -10x, so the next linear entry must be 3x so that the overall sum is 7x.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
1 3x 10
The bottom and final term is 10, which is our desired answer. Therefore, we can now read the quotient off the first column:
3x^4+22x^3+37x^2-7x+10 / 3x + 10 = x^3 + 4x^2 -x + 1
Answer:1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250
Step-by-step explanation:
Answer:
2x(x-3)(-x+1)
Step-by-step explanation:
Factor 2x from everything -> 2x(4x-3-x^2)
Reorder the terms -> 2x(-x^2+4x-3)
Write 4x as a sum -> 2x(-x^2+3x+x-3)
Factor out -x from -x^2+3x looks like -> 2x(-x(x-3)+x-3)
Factor out x-3 from the expression -> 2x(x-3)(-x+1)
Answer:
Step-by-step explanation:
When two angles add up to 90, they are complementary angles
∠a + ∠b = 90
59 + ∠b = 90
∠b = 90 - 59
∠b = 31°
Answer:
x=2
Step-by-step explanation:
The parallel lines divide the transversal into proportional segments that is
(cross multiply)
9(x+4)=54 (divide by both sides by 9)
x+4=6 (subtract 4 from both sides)
x=2
