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3 years ago

How do i know if the "y = " is additon or subtraction?

Mathematics

2 answers:

Andre45 [30]3 years ago

6 0

Answer:

Step-by-step explanation:

tino4ka555 [31]3 years ago

3 0

2x+4y=16
2x+4(4)=16
2x+16=16
-16=-16=2x=0

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In ΔАВС, m∠ACB = 90°, <br> CD<br> ⊥ <br> AB<br> m∠ACD = 30°, and AC = 6 cm. Find BD

myrzilka [38]

It is 9 because you have a 30,60,90 triangle, and then you can use pythagorean theorem.

3 0

2 years ago

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20 ounces into pounds'

evablogger [386]

Answer:

1.25

Step-by-step explanation:

20 ounces would be 1.25 pounds.

Please mark as brainliest! Thanks! If you need anymore help just let me know! :)

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2 years ago

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Three coins are flipped.

Darina [25.2K]

Step-by-step explanation:

when 3 coins are flipped the following outcomes are possible

h = heads, t = tails

h h h

h h t

h t h

h t t

t h h

t h t

t t h

t t t

yes, there have to be 8 options, because we have 3 positions with 2 possible outcomes. that means

2×2×2 = 2³ = 8 possibilities.

at least 2 tails means 2 or 3 t in the list item :

h t t

t h t

t t h

t t t

so, 4 out of the 8 possible outcomes. the probability is then therefore

4/8 = 1/2 = 0.5

8 0

1 year ago

2. Saul invested an average of $425 per month since age 30 in various securities for his

BabaBlast [244]

Answer:

$507.30

Step-by-step explanation:

-Given the monthly deposits are $425 and the interest rate is 3.5% for 30 years.

-The amount of the investment after 30 years is calculated as;

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{30\times 12}\\\\=1212.65$

-Assuming Saul started saving at age 20, his investment term will be 40 yrs.

-His investment amount is thus:

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{40\times 12}\\\\=1719.95$

#We subtract to find how much more he would have if he started saving at 20;

$=A_{20}-A_{30}\\\\=1719.95-1212.65\\\\=507.30$

Hence, Saul would have $507.30 more had he started saving 10 years earlier.

5 0

2 years ago

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.

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2 years ago