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2 years ago

6

Please help!!! 20 points

1 answer:

Luba_88 [7]2 years ago

7 0

Answer:

a

Step-by-step explanation:

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CAN SOMEONE PLEASE HELP WITH QUESTIONS 3 THROUGH 11?? YOU DON’T EVEN HAVE TO DO ALL OF THEM JUST THE ONES U FEEL LIKE DOING (ILL

adell [148]

Answer:

3. 3/2

4. -1/3

5. -3.5

6. -6and 2/3

7. -18and 13/24

8. 1/18

9.-2.6

10.-1.83

11. 14.963

Step-by-step explanation:

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2 years ago

A nest of ants has been growing exponentially in such a way that its population, P, as a function of w weeks is given by P(w)=24

Hunter-Best [27]

Answer:

0.9%

Step-by-step explanation:

Given that:

A nest of ant is represented by the exponential growth function :

P(w)=24,000(1.063)^w

Where w = number of weeks

Recall :

Growth function is generally represented as :

P(t) = A(1 + r)^t

Where ; A is the initial population figure; r = growth rate and t = time

Hence, the growth rate per week of the function given is :

(1 + r) = 1.063

r = 1.063 - 1

r = 0.063

Number of days in a week = 7

Hence, growth rate per day = r /7

0.063 / 7

= 0.009

(0.009 * 100%) = 0.9%

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2 years ago

Two ways technology can affect the environment

Lelu [443]

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2 years ago

Find the LCM of 3,12,16

maria [59]

Answer:

The lcm is 48. Hope this helps

7 0

2 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago