We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )

The standard normal z distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( $\frac{X-\mu}{\sigma}$ < $\frac{5026-4016}{532}$ ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0

2 years ago

What is the reciprocal of 0.125

lesya692 [45]

1/0.125
I really hope this helps

6 0

2 years ago

Help....,................. .

alexandr402 [8]

<span>the x is supposed to represent the amount of miles driven in that car and the numbers in the paranthesis are supposed to be the price of the car or rental cost</span>

6 0

2 years ago