A solution has a pOH of 7. 1 at 10∘c. Then the pH of the solution given that kw=2. 93×10−15 at this temperature is 7.4 .
It is given that,
pOH of solution = 7.1
Kw =2.93×10^(-15)
Firstly, we will calculate the value of pKw
The expression which we used to calculate the pKw is,
pKw=-log [Kw]
Now by putting the value of Kw in this expression,
pKw =−log{2.93×10^(-15)}
pKw =15log(2.93)
pKw=14.5
Now we have to calculate the pH of the solution.
As we know that,
pH+pOH=pKw
Now put all the given values in this formula,
pH+7.1=14.5
pH=7.4
Therefore, we find the value of pH of the solution is, 7.4.
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There are two scales, one is a Ritcher scale and another one is called a Mercalli scale.
Answer:
80 N
Explanation:
you can multiple
force equal to mass x gravity
Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of is 32 g/ mol.
Now,
= 2.83
or, rate of
=
Rate of = 0.022 L/hr.
This means that 0.022 L of gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.