Answer:
Explanation:
Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺ + 2 NO₃⁻
187.5 gm 4M 1 M
187.5 gm reacts with 4 M ammonia
18.8 g reacts with .4 M ammonia
ammonia remaining left after reaction
= .8 M - .4 M = .4 M .
187.5 gm reacts with 4 M ammonia to form 1 M Cu(NH₃)₄²⁺
18.8 g reacts with .4 M ammonia to form 0.1 M Cu(NH₃)₄²⁺
At equilibrium , the concentration of Cu²⁺ will be zero .
concentration of ammonia will be .4 M
concentration of Cu(NH₃)₄²⁺ formed will be 0.1 M
Solid to Gas is Sublimation. Gas to Solid is Deposition.
I had this same question a while back, so I may not be right, but I'm pretty sure it's D. None of the above.
Answer:
Bromine water test
There are two tests to detect the presence of unsaturated double bond in an organic molecule, the bromine water test and Bayer's test. In the bromine water test, when the molecule is added to bromine water, bromine is added to the carbon atoms across the double bond.
45.098 L
45098/1000 = 45.098
