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2 years ago

What are the relative minimum and relative maximum values over the interval [−4, 4] for the function shown in the graph?

Mathematics

2 answers:

mina [271]2 years ago

6 0

Answer:

Step-by-step explanation:

The relative minimum is where the curve changes directions from down to up. The relative maximum is where the curve changes direction from up to down.

In the interval [-4, 4], there are two relative minimums: y=-36. And there is one relative maximum: y=64.

Answer A.

navik [9.2K]2 years ago

3 0

A relative minimum = −36 , relative maximum = 64

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2 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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2 years ago

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Step-by-step explanation:

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1 year ago