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3 years ago

What is the common factor of x^2-9 and x^2+x-6?

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

X^2 - 9 = (x+3)(x-3)

x^2 -5x + 6 = (x-2)(x-3) 

So, the common factor is x-3

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2 years ago

Find the x-intercepts of the parabola with vertex (5,-4) and y-intercept (0,96). Write your answer in this form: (x1,y1),(x2,y2)

lesya692 [45]

Answer:

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

Step-by-step explanation:

we know that

The equation of the given parabola is

$(y-k)=a(x-h)^{2}$

we have

the vertex is the point (5,-4)

substitute

$(y+4)=a(x-5)^{2}$

The y-intercept is the point (0,96)

substitute and solve for a

$(96+4)=a(0-5)^{2}$

$100=a(25)$

$a=100/25=4$

The equation of the vertical parabola is equal to

$(y+4)=4(x-5)^{2}$

Find the x-intercepts

Remember that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$4=4(x-5)^{2}$

Simplify

$1=(x-5)^{2}$

Rewrite

$(x-5)^{2}=1$

square root both sides

$(x-5)=(+/-)1$

$x=(+/-)1+5$

$x=(+)1+5=6$

$x=(-)1+5=4$

therefore

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

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2 years ago

Given a rectangle with lengths of 7 meters and widths of 5 metres,what would be the perimeter

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step by step explanation

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1040 hours at $8 = $8320 per year

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2 years ago