<span>z2 – 2z – 35 = 0
2z - 2z = 35
0 = 35
No solution</span>
Answer:
Step-by-step explanation:
b^2 - 4ac > 0
(-8)^2 - 4(1)(-2) = 64 + 8 = 72
two solutions
Answer:
Here we can use the relationship:
Distance = time*speed.
When Jose walks, his speed is 4 mph.
Then if he walks for X hours, the distance that he will travel is:
D = 4mph*X
When Jose runs, his speed is 8mph.
Then if he runs for T hours, the distance that he will travel is:
D´ = 8mph*Y
And we know that he travels in total 20 miles, then we must have that:
D + D´= 20mi
This leads to:
4mph*X + 8mph*Y = 20mi
Where X is the time that he walked, and Y is the time that he runed.
Then the equation that represents the different amounts of times that Jose runs and walks is:
4mph*X + 8mph*Y = 20mi
Where we can not really find the solutions for Y and X, because there is only one equation and two variables.
