Answer:
Step-by-step explanation:
If you meant f(x) = √x - 1, then the domain is [0, infinity).
If you meant f(x) = √(x-1), then the domain is [1, infinity).
When any ambiguity may rear its ugly head, use parentheses, as indicated here.
a + b = 88 <span>
<span>
</span><span>ab = y
</span><span>
</span><span>a = 88 - b
</span><span>
</span><span>y = (88 - b)*b
</span>
<span>y = -b^2 + 88b
</span><span>
</span><span>Take the derivative and set equal to 0
</span><span>
</span><span>y' = -2b + 88 = 0
</span><span>
</span><span>2b = 88
</span>
<span>b = 44 </span></span>
<span><span>a=44</span></span>
<span><span> both numbers are 44</span></span>
Factors of 4: 2 and 2
y= (x+2)²
+√y or -√y = x+2
x= 2+√y , 2-√y
interchange variables
y= 2+√x , 2-√x
f ⁻¹(x) = 2 + √x, 2 - √x
Answer:
We readily separate the variables and integrate:
∫dP/P=∫(k+bcos2
t)dt
ln P=kt+(b/2)*sin2t+ln C
Clearly C = Po, so we find that P(t) = Poexp(kt + (b/2)* sin 2t). The 271- curve with the typical numerical values P_o = 100, k = 0.03, and b = 0.06. It oscillates about the curve which represents natural growth with P_o and k = 0.03. We see that the two agree at the end of each full year.
note:
find the attached graph
