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2 years ago

Find the difference of 5.95 and 4.7

Mathematics

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

Answer:

1.25 is your answer.

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In the equation z/6 =

Nikitich [7]

Hi there!

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I believe your answer is:

"Isolate the variable using inverse operations."

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Here’s why:

To solve for a variable, we would have to isolate it on one side.

To isolate it, we would use inverse operations on both sides on the equation until the variable is isolated.

There are no like terms in the given equation.

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$\boxed{\text{Solving for 'z'...}}\\\\\frac{z}{6} = 36\\-------------\\\rightarrow (\frac{z}{6})6 = (36)6\\\\\rightarrow \boxed{z = 216}$

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Hope this helps you. I apologize if it’s incorrect.

5 0

2 years ago

Read 2 more answers

5+<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex-formu

solong [7]

Answer is -44+x^2 . First you need to evaluate the equation and get 5+x^2-49 then u calculate it and your final answer is -44+x^2

6 0

2 years ago

In △ ABC and △DEF, AC = DF, AB = DE and < A = Pls help dont scam me pls....

zysi [14]

Answer:

∠A = ∠D (**but very important Δ ABC has to be congruent to Δ DEF)

Step-by-step explanation:

It will help if you draw the triangles out and label the same sides. Then according to the side-angle-side (SAS) rule, ∠A should be equal to ∠D

5 0

2 years ago

5. Solve by using the square root property. (x - 3)² +6=1

Veseljchak [2.6K]

Answer:

x = 3 + i+√5

x = 3 + i-√5

x= 4 - √6

x= 4 +√6

Step-by-step explanation:

(x - 3)² +6=1

(x - 3)² + 6 = 1

-6 -6

sq root > (x - 3)² = -5

x-3 = i±√5 (i because neg. number)

x = 3 + i±√5

since its ±

two possible answers

x = 3 + i+√5

x = 3 + i-√5

(x - 3)² +6=1

(x-3)+ √6= √ 1

x-3 = 1 - (±) √6

x= 4 - (±) √6

Answers

x= 4 - √6

x= 4 +√6

6 0

2 years ago

Express the complex number in trigonometric form -6 + 6sqrt3i

marusya05 [52]

$\large\begin{array}{l}\\\\ \textsf{This is a complex number in }\mathsf{a+bi}\textsf{ form:}\\\\ \mathsf{z=-6+6\sqrt{3}\,i}\\\\ \textsf{where }\mathsf{a=-6~~and~~b=6\sqrt{3}.} \end{array}$

$\large\begin{array}{l}\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the absolute value of z (complex modulus of z):}\\\\ \mathsf{|z|=\sqrt{a^2+b^2}}\\\\ \mathsf{|z|=\sqrt{(-6)^2+(6\sqrt{3})^2}}\\\\ \mathsf{|z|=\sqrt{36+36\cdot 3}}\\\\ \mathsf{|z|=\sqrt{36\cdot 108}}\\\\ \mathsf{|z|=\sqrt{144}}\\\\ \mathsf{|z|=12} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi$

$\large\begin{array}{l}\textsf{For }\mathsf{z=-6+6\sqrt{3}\,i,}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{-6}{12}=-\,\dfrac{1}{2}}\\\\ \mathsf{sin\,\theta=\dfrac{6\sqrt{3}}{12}=\dfrac{\sqrt{3}}{2}} \end{cases}\\\\\\ \textsf{Since}\\\\ \mathsf{cos\,\theta0,}\\\\ \theta\textsf{ lies in the 2}\mathsf{^{nd}}\textsf{ quadrant.}\\\\\\\textsf{Therefore,}\\\\ \mathsf{\theta=\dfrac{2\pi}{3}~rad~~(120^\circ)} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}$

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$\large\textsf{I hope it helps.}$

Tags: complex number trigonometric form trig absolute value modulus argument angle

4 0

2 years ago