Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
Step-by-step explanation:
F is the answer to this question
N=0 bc you remove the parentheses, cancel the equal terms what would be 6 being cancel it would look like -24n=3n now and move the variable to the left collet like terms and then you will divide the sides. Your answer is 0
If they have 11 boxes and 88 shorts there will be 8 shorts in each box
