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2 years ago

Probability:

Mathematics

1 answer:

HACTEHA [7]2 years ago

6 0

A: We want to select one person who works out three days a week. Our probability is simply 12/80 ~~ 15%

B: At least 4 days a week means 4 days, 5 days, or 6 days.
Hence, we have: (9 + 20 + 8)/80 = 46%

C: At least once a week.
Let's find out how many DO NOT work out and subtract that from our sample space. This means they must work out at least once a week.

(80 - 15)/80 = 81%

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An arithmetic sequence has this recursive formula: What is the explicit formula for this sequence? A. an = (–1) + (n – 7)(–4)

tresset_1 [31]

bearing in mind that an explicit form is simply the sequence written as a function of some variables, so we simply simplify and add like-terms.

$\bf a_n=(-1)+(n-7)(-4)\implies a_n=-1+(-4n+28)\implies a_n=27-4n$

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3 years ago

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Let x=number of cds and y=number of dvds

Elis [28]

X + y = 40.....multiply by -4
4x + 6y = 180
-------------------
-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
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2y = 20
y = 20/2
y = 10 <===

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2 years ago

Must Just one match to fix the equation ?<br> 6 + 4 = 4

zhannawk [14.2K]

Answer:

6 + 4 × -2/4 = 4

Step-by-step explanation:

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2 years ago

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Marrrta [24]

Given:

A figure of a circle and two secants on the circle from the outside of the circle.

To find:

The measure of angle KLM.

Solution:

According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.

Using intersecting secant theorem, we get

$\angle KLM=\dfrac{1}{2}(Arc(JON)-Arc(KM))$

$(3x-4)=\dfrac{1}{2}(271-(x+6))$

$(3x-4)=\dfrac{1}{2}(271-x-6)$

Multiply both sides by 2.

$6x-8=265-x$

Isolate the variable x.

$6x+x=265+8$

$7x=273$

Divide both sides by 7.

$x=\dfrac{273}{7}$

$x=39$

Now,

$\angle KLM=(3x-4)^\circ$

$\angle KLM=(3(39)-4)^\circ$

$\angle KLM=(117-4)^\circ$

$\angle KLM=113^\circ$

Therefore, the measure of angle KLM is 113 degrees.

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2 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

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2 years ago

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