Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
ANSWER
EXPLANATION
Part a)
Eliminating the parameter:
The parametric equation is
From the first equation we make t the subject to get;
We put it into the second equation.
We differentiate to get;
At x=5,
The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by
Without eliminating the parameter,
At x=5,
This implies that,
The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by
Answer:
Y= -4 :)
Steps:
Apply rule
-y + 3 = 7
Subtract 3 from both sides
-y + 3 - 3 = 7 - 3
Simplify
-y = 4
Divide both sides by -1
-y/-1 = 4/-1
Simplify
y = -4
Answer:
$63
Step-by-step explanation:
The store is 20% off, Jessica has a coupon that is 5% off add that together and it's 25% off. $84 - 25% = $63