Answer:
5:40
Step-by-step explanation:
This is a problem involving the least common difference.
If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.
The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.
Red:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80
Blue:
10, 20, 30, 40
You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.
We are given with the sequence -20, -16, -12, -8. From this sequence, we can see that the arithmetic difference is +4, from -(-20 + 16). hence following the arithmetic formula of an = a1 + d *(n-1). Substituting, an = -20 + 4 *(n-1) where n is an integer
Is this the whole question ?
Answer:
50, 40, 30, 250, 350
Step-by-step explanation:
1/2 = 0.5, 0.5 x 100 = <u>50</u> (0.5 -> 5 -> 50)
2/5 = 0.4 (10 / 5 [the denominator] = 2, 0.2 x 2 [the numerator] = 0.4), 0.4 x 100 = <u>40</u> (0.4 -> 4 -> 40)
3/10 = (10 / 10 [the denominator] = 1, 0.1 x 3 [the numerator] = 0.3), 0.3 x 100 = <u>30</u> (0.3 -> 3 -> 30)
5/2 = 2.5 (2 1/2), 2.5 x 100 = <u>250</u> (2.5 -> 25 -> 250)
7/2 = 3.5 (3 1/2), 3.5 x 100 = <u>350</u> (3.5 -> 35 -> 350)
Note: I'm not sure if I understand the question completely, but I changed the fraction into a decimal and multiplied it by 100. Not sure what it means by "<u><em>Divide</em></u><em> fraction</em>".
