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2 years ago

10

Which describes how the same force affects a small mass and a large mass

1 answer:

goldenfox [79]2 years ago

5 0

You shall use the equation for force given by the second Law of Newton, this is F = m*a, where F is the net force that acts over the object, m is the mass of the object and a is the acceleration that the object will acquire. From that equation you can find a = F/m, which means that a is direct proportional to F and invsersely related to m. So, small masses accelerate faster than large masses, and <span>the answer is the option B. the small mass accelerates faster.</span>

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Addition of a metal slab of thickness "a" between the plates of a parallel plate capacitor of plate separation "d" is equivalent

Crazy boy [7]

Answer:

$K = \frac{d}{d+a}$

Explanation:

The capacitance of a capacitor in terms of the dielectric constant, area of the plate and the distance separating the plate is given by:

$C = \frac{\epsilon A}{d}$

Where A = Area of the plate

d = distance between the plates

$\epsilon =$ dielectric constant

Case 1:

When a meta slab of thickness, a, is added between the plates of the parallel plate capacitor , the effective separation between the plates becomes d+a

Therefore the capacitance of the capacitor becomes:

$C = \frac{\epsilon A}{d + a}$ .......................(1)

Case 2:

Introducing a dielectric with dielectric constant K between the plates, the capacitance of the capacitor becomes:

$C = \frac{K\epsilon A}{d}$ .........................(2)

Equating (1) and (2)

$\frac{K\epsilon A}{d} = \frac{\epsilon A}{d+a}\\\frac{K}{d} = \frac{1}{d+a} \\K = \frac{d}{d+a}$

3 0

2 years ago

Two solenoids of equal length are each made of 2000 turns of copper wire per meter. Solenoid I has a 5.00 cm radius; solenoid II

Nookie1986 [14]

Answer:

BI/BII = 1

Explanation:

The magnetic field due to a solenoid is given by the following formula:

$B = \mu nI\\$

where,

B = Magnetic Field due to solenoid

μ = permeability of free space

n = No. of turns per unit length

I = current passing through the solenoid

Now for the first solenoid:

$B_1 = \mu n_1I_1 \\$

For the second solenoid:

$B_2 = \mu n_2I_2\\$

Dividing both equations:

$\frac{B_1}{B_2} = \frac{\mu n_1I_1}{\mu n_2I_2}\\$

here, no. of turns and the current passing through each solenoid is same:

n₁ = n₂ and I₁ = I₂

Therefore,

$\frac{B_1}{B_2} = \frac{\mu nI}{\mu nI}\\$

<u>BI/BII = 1</u>

5 0

2 years ago

What is true about surface waves?

fredd [130]

B. is the correct answer

6 0

2 years ago

Read 2 more answers

Use the table of electric force between objects in two different interactions to answer the question. Interaction Charge on Obje

forsale [732]

Answer:?that’s a lot

Explanation:

6 0

2 years ago

The velocity versus time graph of particle A is tangent to the velocity versus time graph for particle B at point O. What is the

Fudgin [204]

Answer: C. -1.16 meters/second2

Explanation:

A= v/t (velocity/time)

in this case: v=7 and t=6

So, A= 7/6

A=1.16

The graph is decreasing so accelleration would be negative

A= <u>-1.16 meters/second2</u>

<u>Option C!</u> ; )

<u></u>

3 0

2 years ago