Answer:
1. KCLO3------>KCL + 3/2O2(g)
2. 122.5g/mol
3. 0.2mol
4. 18.5g
20(50) = 40(V₂)
⇒1000 = 40V₂
⇒V₂ = 1000/40
⇒ V₂ = 25 mL
Explanation:
wheres the question??????