Answer:
The correct answer is 29 grams.
Explanation:
Based on the given question, the reaction will be,
CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3
The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.
Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.
Therefore, 28 grams of butene when reacts with hydrogen gas to give,
= 58/56 * 28 = 29 grams of butane.
Hence, the mass of butane produced will be 29 grams.
The balanced chemical
reaction will be:
C4H8 + 6 O2 --> 4 CO2 + 4 H2O
We are given the amount of butene being combusted. This will be our
starting point.
136.6 g C4H8 (1 mol C4H8/ 56.11 g C4H8) (4 mol CO2/1 mol <span>C4H8</span>) ( 44.01 g CO2/ 1 mol CO2) = 428.6 g CO2
Answer:
0.74mol
Explanation:
4.5×10^23/6.02×10^23=0.74mol
Answer:
Explanation:
According to the boiling point elevation law described by the equation , the increase in boiling point is directly proportional to the van 't Hoff factor.
The van 't Hoff factor for nonelectrolytes is 1, while for ionic substances, it is equal to the number of moles of ions produced when 1 mole of salt dissolves.
would produce 2 moles of ions per 1 mole of dissolved substance, sodium and bromide ions.
is insoluble in water, so it would barely dissociate and wouldn't practically change the boiling point.
would dissociate into 3 moles of ions per 1 mole of substance, two potassium cations and one sulfide anion.
is a gas, it would form some amount of carbonic acid when dissolved, however, carbonic acid is molecular and would yield i value of i = 1.
Therefore, potassium sulfide would raise a liquid's boiling point the most if all concentrations are equal.