The proabability would be 50% always
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
Answer:
Step-by-step explanation:
Start
<F = <Q Given
<GPF = <RPQ Vertically opposite angles
<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal
Triangle GPF ~ Triangle RPQ AAA
end
I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.
20
JL/LE = 90/27 Given
KL /LD = 90/27 Given
<JLK = <DLK Vertically opposite
Are the ratios equal Yes Then is the angle included Yes
Then the triangles are similar.
Are the ratios not equal No then the triangles cannot be similar
Is the angle not included Then similarity cannot be proved.
ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity
The answer is 5. this can be found by creating a factor tree of both numbers
