Two protons are 1 × 10−10 m apart (about one atomic radius). Which interaction between two protons is stronger, the gravitationa
l attraction or the electric repulsion? Note that since both the gravitational and electric forces depend on the inverse square distance, this comparison holds true at all distances, not just at a distance of 1 × 10−10 m. Use the accurate values of G = 6.67 × 10−11 N·m2/kg2, proton mass of 1.67 × 10−27 kg, and electron mass of 9.11 × 10−31 kg.
a) First, calculate the electric force |Felec| = ___ N
b) Next, calculate the gravitational force |F grav| = ___ N
c) Calculate the ratio of the two forces |Felec|/|Fgrav| = ___
a) First, calculate the electric force |Felec| = ___ N
b) Next, calculate the gravitational force |F grav| = ___ N
c) Calculate the ratio of the two forces |Felec|/|Fgrav| = ___
1 answer:
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Answer:
<h2>39.2 m</h2>Explanation:
The height of the hill side can be found by using the formula
p is the potential energy
m is the mass
From the question we have
We have the final answer as
<h3>39.2 m</h3>Hope this helps you