Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
the number of adult ticket sold is 107 tickets
Step-by-step explanation:
The computation of the number of adult ticket sold is shown below:
Let us assume the number of tickets be x,
So, the adult be x
And for student it would be 3x
Students= 2x
Adults= x
Total = 4x
Now the equation could be
4x = 428
x = 107
This x signifies the adult tickets sold i.e 107
Hence, the number of adult ticket sold is 107 tickets
Answer:
40:16, 16:40, 40/16, 16/40
Answer:
Step-by-step explanation:
This is an incomplete problem. Other data were not given.
Given:
Profit of every sandwich = $2
Profit of every wrap = $3
x = sandwich
y = wrap
Last month: 2x + 3y = 1,470
Next month: 2x + 3y = 1,593
Based on the given equation:
Both still have the same profit. $2 for sandwiches and $3 for wraps.
The only reason why there is a difference in the total amount is the change in the number of sandwich or wrap sold in a given month.
Since, next month's total sale is higher than last month's total sale, it is safe to assume that the sale of sandwich or wrap is higher than last month's sale.
The answer is 32 cm. for the hexagon
