Answer:
1.The Sun is located at one of the foci of the planets' elliptical orbits.
2.The path of the planets around the Sun is elliptical in shape.
Explanation:
As per Kepler's law of planet motion we know that all planets revolve around the sun in elliptical path in such a way that position of Sun must be at one of the focii of the path
So all planets are in elliptical path always
Position of sun is always at one of the focus
so correct answer will be
1.The Sun is located at one of the foci of the planets' elliptical orbits.
2.The path of the planets around the Sun is elliptical in shape.
Answer:
Light's angle of refraction = 37.1° (Approx.)
Explanation:
Given:
Index of refraction = 1.02
Base of refraction = 1
Angle of incidence = 38°
Find:
Light's angle of refraction
Computation:
Using Snell's law;
Sin[Angle of incidence] / Sin[Light's angle of refraction] = Index of refraction / Base of refraction
Sin38 / Light's angle of refraction = 1.02 / 1
Sin[Light's angle of refraction] = Sin 38 / 1.02
Sin[Light's angle of refraction] = [0.6156] / 1.02
Sin[Light's angle of refraction] = 0.6035
Light's angle of refraction = 37.1° (Approx.)
<span>law of conservation of </span>energy<span> is </span><span><span>states that energy of the universe remains constant cant be created nor destroyed and conserving energy is not using as much power as you was like trying to make power bill lower while law of conservation is constant </span> </span>
Answer:
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Explanation:
Let n be the number of the vernier scale division which coincides with the main scale division. Rotate the vernier caliper 90° and repeat the steps 4 and 5 for measuring the internal diameter in perpendicular direction. To measure the depth, find the total reading and zero correction.
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Answer:
The acceleration is in 2 D as in between east and south.
Explanation:
mass, m = 50 kg
acceleration, a = 0.25 m/s^2 horizontal
acceleration of elevator, a' = 1 m/s^2 downwards
When a person on the ground the resultant acceleration of the person with respect to the ground is between east and south direction so the path os parabolic in nature. It graph is shown below:
