Answer:
3, 2, 2
Step-by-step explanation:
Subtract 7.8 points by 4.8 and you get 3.4 !!
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
Answer: find the answer in the explanation
Step-by-step explanation:
Given that the transformed graph is of function f(x) = (x + 2)^4 + 6 and the parent function g(x) = x^4
The transformed graph function g(x) was shifted two (2) units to the left and was translated six (6) units upward.
When the function is shifted to the right, the factor of x will be negative and when it's shifted to the left, the factor of x will be positive.
Therefore, function g(x) = x^4 is shifted 2 units to the left and translated 6 units upward to form f(x) = ( x + 2 )^4 + 6.
