Answer:
Step-by-step explanation:
The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :
Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.
Here; population mean, μ = 10 ; the claim is now that, μ < 10 based on what was observed about the sample.
H0 : μ = 10
H0 : μ < 10
If we wanted to test If the mean was greater than 10 ; then the sign is reversed
H0 : μ = 10
H0 : μ > 10
If we wanted to test If the score is just different from the mean score stated ; (it may be less than or greater than)
H0 : μ = 10
H0 : μ ≠ 10
Answer:
I really don't get your question
Answer:
Step-by-step explanation:
A) Stem-and-leaf plot
stem leaf
5 1
7 6,7,8,9
8 1,2,4,6
9 9
B) Outlier
Could consider 51 an outlier.
AB is congruent to side DE.
So,
AB= 23 and DE= 23
I hope this helps!
~kaikers
Answer: 0.6827
Step-by-step explanation:
Given : Mean IQ score :
Standard deviation :
We assume that adults have IQ scores that are normally distributed .
Let x be the random variable that represents the IQ score of adults .
z-score :
For x= 90
For x= 120
By using the standard normal distribution table , we have
The p-value :
Hence, the probability that a randomly selected adult has an IQ between 90 and 120 =0.6827