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2 years ago

Consider the function f(x) = x2 + 12x + 11. x-intercepts?

Mathematics

2 answers:

IrinaK [193]2 years ago

8 0

The x-intercepts of this function are -11 and -1.

The easiest way to find the intercepts of this graph is by factoring. To factor a quadratic, we look for factors of the last number, that add up to the middle number. Below are the factors of the last number.

1 and 11

-1 and -11

Now we look for one that adds up to positive 12.

1 and 11

-1 and -11

Since these two add up to the middle number, we can use them in parenthesis with x + and factor. If there was not a pair, we would then have to use the quadratic equation.

f(x) = (x + 1)(x + 11)

Now to solve for the x-intercepts, we set each parenthesis equal to 0 and solve for x.

x + 1 = 0

x = -1

x + 11 = 0

x = -11

Nitella [24]2 years ago

6 0

Answer:

x intercept: (-1,0) & (-11,0)

y intercept: (0,11)

Step-by-step explanation:

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Step-by-step explanation:

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1 year ago

Kumar bought some mangoes. The price of each mango () is found to be 6 more than the total number of mangoes bought by him and t

spayn [35]

Answer:

Price = 20, Amount = 14

Step-by-step explanation:

A = Amount of Mangoes

P = Price for 1 Mango

P = A + 6

280 = P * A

insert A+6 for P

280 = (A+6) * A

280 = 6A + A²

280=1*a^2+6*a | Vertausche beide Seiten der Gleichung.

1*a^2+6*a=280 | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2

1*a^2+6*a+(3)^2=3^2+280 | Rechne 3 hoch 2 aus.

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1*a^2+6*a+(3)^2=9+280 | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.

1*(1*a+(3))^2=289 | Auf beiden Seiten Quadratwurzel ziehen.

1*a+(3)=+-*289^0.5

1*a_1+(3)=289^0.5

1*a_1+3=289^0.5 | Ziehe die Wurzel aus 289

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2 years ago

The Freedom Trail is 2 1/2 miles long. Ana walked 5/8 mile from Boston Common to the Paul Revere House. Then, she walked 3/8 mil

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1 1/2 miles

Step-by-step explanation:

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2 years ago

A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t

Andre45 [30]

Answer: Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

Step-by-step explanation:

Given: Width of pencil box = $5\dfrac14\text{ inches}=\dfrac{21}{4}\text{ inches}$

Width of seven pencils = $2\dfrac58\text{ inches}=\dfrac{16+5}{8}\text{ inches}=\dfrac{21}{8}\text{ inches}$

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$\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}$