Answer:
Input is the value of w and the function f = 24/w as length x breadth = area of rectangle
If w = 0.5, then f = 24/0.5 = 48cm. So, it is a possible input of the function.
If w = 48, then f = 24/48 = 0.5cm. So, it is a possible input of the function.
If w = 0, then f = 24/0 = 0cm. So, it is not a possible input of the function as it cannot be defined
If w = -6, then f = 24/-6= -4cm. So, it is not a possible input of the function as a length and width can't be negative
If w = 3, then f = 24/3 = 8cm. So, it is a possible input of the function.
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
b because the value are correct
Step-by-step explanation:
Answer:
h
Step-by-step explanation:
h
Answer:
6
Step-by-step explanation:
4(3)+(2)^2-(5)^2
12+4-10
16-10
6