Question

Find the distance from the point to the given plane. (1, −7, 8), 3x + 2y + 6z = 5

Answer 1

3x + 2y + 6z = 5?? 
then 
distance = |3(1) + 2(-2) + 6(4) - 5| / √(3^2 + 2^2 + 6^2) 
the plane is ax + by + cz - d = 0 while the point is (x1, y1, z1)