n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer: 2.5
Step-by-step explanation:
y = rx
substitute numbers in and solve for r
if
y = 10
x = 4
then
10 = r4
r = 10/4 = 2.5
this works for all the other numbers and always gives r = 2.5
Hello :
3x3 – 11x2 – 26x + 30 divided by x – 5 is :<span>3x2 + 4x – 6
because :
(x-5)(3x²+4x-6)=3x^3+4x²-6x-15x²-20x+30 =</span>3x3 – 11x2 – 26x + 30
Answer:
If you take 32 percent of a number and get 64, then what is that number? In other words, you know that 32 percent of a number is 64 and you want to know what that initial number is. Therefore, the answer to "64 is 32 percent of what number?" is 200, and you can also derive that 32 percent of 200 equals 64.
Step-by-step explanation:
Answer:
14x
Step-by-step explanation:
multiply the 2i by the 0 eulogistic quotient
