if a safety switch has a 1 in 10 chance of failing, how many switches would a company want to install in order to have only a 1
2 answers:
Because every individual switch has a 1/10 chance of failing, two switches will have a (1/10)*(1/10) chance of failing. Three switches will have a (1/10)*(1/10)*(1/10) chance of failing. This pattern will continue. Because 
equals 1/1,000,000, 6 switches will give you a 1 in 1 million chance of all failing at the same time.
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Each row has two more boxes than the row above. The first row has one box
The boxes in a row form an arithmetic sequence with the first term, a₁ = 1 and the common difference, d=2.
The n-th term is
The sum of n terms is
Answer:
The table will have the following:
Row Number: 1 2 3 4 5 6
Boxes in the row: 1 3 5 7 9 11
Total boxes in the display: 1 4 9 16 25 36
The boxes in a row form an arithmetic sequence with the first term, a₁ = 1 and the common difference, d=2.
The n-th term is
The sum of n terms is
Answer:
The table will have the following:
Row Number: 1 2 3 4 5 6
Boxes in the row: 1 3 5 7 9 11
Total boxes in the display: 1 4 9 16 25 36