HELP PLEASE!! Write an equation in slope-intercept form of the line with slope −6/5 that contains the point (−5,3).
2 answers:
Answer:
Step-by-step explanation:
we know,
Equation of line with slope m
and passing through (x1,y1) is,
y-y1=m(x-x1)
here, slope= -6/5 and the point is (-5,3)
So, the equation is,
Multiplying by 5
Dividing by 5
Answer: y = -6/5 x - 3
Solution :
The equation of line is
y = mx + b
y = y coordinate
m = slope
x = x coordinate
b = y intercept
so to write the equation of line we need to find the y-intercept (b)
substitute the slope (-6/5) and coordinates given (-5,3) ,
y = mx + b
3 = (-6/5) (-5) + b
3 = 6 + b
3 - 6 = b
-3 = b
So the equation would be,
y = mx + b
y = -6/5 x - 3
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Answer:
The answer is letter D.
Step-by-step explanation:
320/80
=4