Y = mx + b
slope(m) = 3/2
(5,9)...x = 5 and y = 9
now we sub and find b, the y int
9 = 3/2(5) + b
9 = 15/2 + b
9 - 15/2 = b
18/2 - 15/2 = b
3/2 = b
so ur equation is : y = 3/2x + 3/2.........(3,a)....so x = 3
y = 3/2(3) + 3/2
y = 9/2 + 3/2
y = 12/2
y = 6
so ur missing value is 6...a (or y) = 6
Answer:
D
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
If m > 0 , then line slopes upwards from left to right
If m < 0 , then line slopes downwards from left to right
y = 3x - 2
has m > 0 and c = - 2 , thus line slopes upwards crossing the y- axis at - 2
y = - 2x + 3
has m < 0 and c = 3, thus line slopes downwards crossing the y- axis at 3
on the graph this is the lower blue line and the red line
the solution to the system is at the point of intersection of the 2 lines
This is at point D
Answer:
C
Step-by-step explanation:
Answer:
3 3/4 cups of sugar
Step-by-step explanation:
Answer:
Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .
*angles in a quadrilateral is 360 degree
*2x+3x+5x+8x=360
*18x=360
*x=360/18
*x=20
now substitute x in these:
2x=2x20=40
3x=3x20=60
5x=5x20=100
8x=8x20= 160
so these are the following angles: 40,60,100 and 160