Answer:
Given that
Dry-bulb temperature(T) =24°C
Wet-bulb temperature(Tw) = 17°C
Pressure ,P = 1 atm
As we know that psychrometric chart are drawn at constant pressure.
From the diagram
ω= specific humidity
Lets take these two lines Dry-bulb temperature(T) line and Wet-bulb temperature(Tw) cut at point P
From chart at point P
a)
Specific humidity,ω = 0.00922 kg/kg
b)
The enthalpy ( h)
h=47.59 KJ/kg
c)
The relative humidity, RH
RH= 49.58 %
d)
Specific volume ,
v= 0.853 m³/kg
Answer:
1440 × 10⁴ N/C
Explanation:
Data provided in the question:
Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m
a = 7.5 cm = 0.075 m
Now,
Electric field due to a line charge at a distance 'a' is given as:
Ex(P) =
also,
we know
= 9 × 10⁹ Nm²/C²
Thus,
we have
Ex(P) =
therefore,
Ex(P) =
= 1440 × 10⁴ N/C
Answer:
A. The wires will be arranged in order of increasing resistance.
Explanation:
The resistance of a wire is given by
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
In this problem we have several wires made of the same material (so, same ) and same length (same L): so, the only quantity that changes is their thickness, so their value of A.
We see from the formula that the resistance R is inversely proportional to the cross-sectional area A: therefore, the smaller the value of A, the larger the value of R. This means that if we arrange the wires in order of decreasing thickness, we are arranging the wires in order of increasing resistance.