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Answer:
The value of the expression increases as j decreases
Step-by-step explanation:
Let
As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.
For example:
When j = 1, f(j) = 150 - (300*1) = -150
When j = 0.5, f(j) = 150 - (300*0.5) = 0
When j = 0. f(j) = 150 - (300*0) = 150
It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases
So, she has 3hrs to grade all papers, for 35 students.. alrite.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.