Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.
There is 3/4 cup of whatever in one serving. If that serving amount changed to 2, then the 3/4 would be multiplied by 2. If there is half a serving, then it would be divided by 2. There is a constant change, and not one that is always changing.
To find compound probability, multiply the probability of the first and second events. In this case, if you wanted to draw the green first and then the blue, 10/24 or 5/8 times 6/23 equals 30/184 which reduces to 15/92.
First you have to subtract 1350-1000 to get 350. Then you have to make 350/1000 into a percent. First you have to turn it into a decimal. In the fraction 350/1000 can be reduced to 35/100. In decimal form it would be 0.35. In pecentage form it would be 35%. The percentage difference of the student population would be 35%.
