Plz help me calculate this
2 answers:
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Answer: 0.8461
Step-by-step explanation:
Given :
Let x be the random variable that represents the cost for the hospital emergency room visit.
We assume that cost for the hospital emergency room visit is normally distributed .
z-score for x=1000 ,
Using z-value table , we have
P-value =P(x>1000)=P(z>-1.02)=1-P(z≤ -1.02)=1-0.1538642
=0.8461358≈0.8461 [Rounded nearest 4 decimal places]
Hence, the probability that the cost will be more than $1000 = 0.8461
Answer:
The correct option is A) A number line is shown from negative 10 to 0 to positive 10. There are increments of 2 on either side of the number line. The even numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 6 is shown. Above this, another arrow pointing from negative 6 to negative 4 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.
Step-by-step explanation:
Consider the provided expression.
−6 − (−2)
Open the parentheses and change the sign.
−6 − (−2)
−6 + 2
Subtract the numbers.
−4
Now draw this on number line.
First draw a number line is shown from −10 to 0 to 10. with scale of 2 unit on either side of the number line. Draw an arrow pointing from 0 to −6 Which show −6. Above this, another arrow pointing from −6 to −4 which shows −6 − (−2) = −4. A vertical bar is shown at the tip of the arrowhead of the top arrow.
The required number line is shown in the figure 1.
Hence, the correct option is A) A number line is shown from negative 10 to 0 to positive 10. There are increments of 2 on either side of the number line. The even numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 6 is shown. Above this, another arrow pointing from negative 6 to negative 4 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.
