What is the center of a circle whose equation is x^2+y^2-12x-2y+12=0
2 answers:
Answer:
centre = (6, 1 )
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given
x² + y² - 12x - 2y + 12 = 0
Collect the x and y terms together and subtract 12 from both sides
x² - 12x + y² - 2y = - 12
To obtain the equation in standard form use completing the square
add ( half the coefficient of the x/ y term )² to both sides
x² + 2(- 6)x + 36 + y² + 2(- 1)y + 1 = - 12 + 36 + 1
(x - 6)² + (y - 1)² = 25 ← in standard form
with centre = (6, 1 ) and radius = = 5
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Answer:
The selections are dependent.
Yes, they can be treated as independent (less than 5% of the population).
Step-by-step explanation:
Since the selections are made without replacement, each selection affects the outcome of the next selection and, therefore, the selections are dependent.
Although they are dependent, the selections can be treated as independent if the sample size is no more than 5% of the total population. In this case, the sample size is 1235 adults out of a population of 15,958,866 adults. The percentage represented by the sample is:
Thus the selections can be treated as independent for the purposes of calculations.