Answer:
It's B ( just did it )
Step-by-step explanation:
Looked up the answer real quick and the person had the same question with a picture.
It's on Ed2020 it's B
Keep in mind that, when the logarithm base is not explicitly written, base 10 is assumed, therefore,
<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
OPtion B
Step by step explanation:
Lets plug in a random value for x.
Lets say 5 is x
-8(-5-5)=(y+1)^2
5-5 = 0
-8(0) = 0
0 = (y+1)^2
Square root of both sides
0 = y+1
subtract one from both sides
-1 = y
that means the x is 5 and the y is -1. Option B illustrates exactly that!
The integer would be
positive 5
