Answer:
Step-by-step explanation:
This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,
p = 1 - 0.81 = 0.91
n = 9 students
x = number of success = 3
The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,
P(x = 2) = 0.297
4.6 - 3.9= .7cm which is 7mm
X^2-6x+7=0
-b +/- sqrt b^2-4ac all over 2a
a=1 b= -6 and c=7
6+/- sqrt 36-4×1×7 all over 2×1
6+/- sqrt 8 all over 2
6+/- 2sqrt2 all over 2
reduce
3+/- sqrrt2
Let us assume last year the price of the item = $x.
After increase in price by 15% the new price = x + 15% of x = x+ 0.15x = 1.15x.
There is a 25% discount for employee.
25% of 1.15x = 0.25 × 1.15x = 0.2875 x.
Price after discount = 1.15x - 0.2875 x = 0.8625x.
The employee pays $172.50.
Therefore,
0.8625x = 172.50.
Dividing both sides by 0.08625.
<h3>x=200.</h3><h3>Therefore, last year the price was $200.</h3>
