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2 years ago

Which is colder dry ice or dioxide gas

Chemistry

2 answers:

Eddi Din [679]2 years ago

8 0

Dry ice is the solid form of dioxide gas , and I think dry ice is colder because its frozen

Juli2301 [7.4K]2 years ago

6 0

Dioxide gas because ita cooler

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(a) Given that Ka for acetic acid is 1.8 X 10^-5 and that for hypochlorous acid is 3.0 X 10^-8, which is the stronger acid? (b)

Gala2k [10]

Answer:

HOAc is stronger acid than HClO

ClO⁻ is stronger conjugate base than OAc⁻

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

Explanation:

Assume 0.10M HOAc => H⁺ + OAc⁻ with Ka = 1.8 x 10⁻⁵

=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺

Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸

=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺

HOAc delivers more H⁺ than HClO and is more acidic.

Kb = Kw/Ka, Kw = 1 x 10⁻¹⁴

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

4 0

2 years ago

Summarize the Natural Processes of weathering ,erosion, and deposition

Lena [83]

Answer:

I won’t do it in paragraph form cuz it will look very choppy but here you go:

Weathering is when the weather itself changes something, like when a metal bike gets rusty after sitting outside for a long time, or when a plant grows out of concrete.

Erosion is when something gets eroded away at. Like when something has water or wind is flowing against it so much that it changes shape. This is how canyons are made.

Deposition is when a gas turns into a solid, removing energy and skipping the liquid step (frost forming on car window)

7 0

2 years ago

Read 2 more answers

What is the mass of 1.84 mol NaCl? Give your

Sphinxa [80]

Answer:

108 g

Explanation:

3 0

2 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

2 years ago

How are Transpiration and Photosynthesis connected to each other?

dexar [7]

Answer:

A leaf needs carbon dioxide and water for photosynthesis. ... For carbon dioxide to enter, the stomata on the surface of the leaf must be open. As you have seen, transpiration draws water from the roots into the leaf mesophyll.

I hope this helps you :)

7 0

2 years ago