so... you tells us, which filling rate is the bigger and thus faster one?
Answer:
x = -8
y = 7
Step-by-step explanation:
5x + 7y = 9
2x - 3y = -37
1.) First, multiply each side to match either y-values or x-values. (In this example, we'll use match x-values)
10x + 14y = 18 (multiplied by 2)
10x - 15y = -185 (multiplied by 5)
2.) Then, subtract the entirety of one equation to isolate the y-value.
10x + 14y = 18
-10x + 15y = 185
3.) Add and subtract values and divide to find y.
29y = 203
y = 7
4.) Plug-in y to solve for x into one equation, or repeat steps 1-3.
15x + 21y = 27
14x - 21y = -259
29x = -232
x = -8
The answer is (3600 - 900π) ft²
Step 1. Find the radius r of circles.
Step 2. Find the area of the portion of the field that will be watered by the sprinklers (A1)
Step 3. Find the total area of the field (A2)
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A)
Step 1. Find the radius r of circles
r = ?
According to the image, radius of a square is one fourth of the field side length:
r = s/4
s = 60 ft
r = 60/4 = 15 ft
Step 2. Find the area of the portion of the field that will be watered by the sprinklers.
The area of the field that will be watered by the sprinklers (A1) is actually total area of 4 circles with radius 15 ft.
Since the area of a circle is π r², then A1 is:
A1 = 4 * π r² = 4 * π * 15² = 900π ft²
Step 3. Find the total area of the field (A2)
The field is actually a square with side s = 60 ft.
A2 = s² = 60² = 3600 ft²
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A).
To get the area of the portion of the field that will not be watered by the sprinklers (A) we need to subtract the area of 4 circles from the total area:
A = A2 - A1
A = (3600 - 900π) ft²
Answer:
5.5 days (nearest tenth)
Step-by-step explanation:
<u>Given formula:</u>
- = initial mass (at time t=0)
- N = mass (at time t)
- k = a positive constant
- t = time (in days)
Given values:
- = 11 g
- k = 0.125
Half-life: The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.
To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:
Therefore, the substance's half-life is 5.5 days (nearest tenth).
Learn more about solving exponential equations here:
brainly.com/question/28016999
Assuming that she goes every day of the month and one month has 30days:
Let the fee per class of Fit Fast be x.
Let <span>the fee per class of Stepping Up be y.
Let </span><span>the fee per month of Stepping Up be z.
Fit fast fee(if she does for this choice) - 30x
Stepping up fee</span><span>(if she does for this choice) - 30y + z
Im not sure of what the costs are as you did not state but here it is...hope this helps:)</span>