Answer:
It should be reported as 20.648%
Step-by-step explanation:
Since we have 2 different observed values hence we shall use an average of the 2 values to report the result
Thus value is
As we can see that the least count of our observations is upto 3 decimal places hence we have to report a result upto only 3 decimal places thus we need to round off the fourth decimal place thus the digit shall be increased by 1 since we have to drop off 5 and the digit before 5 is 7 which is an odd number.
Thus the result shall be 20.648%
Answer:
(b) (x -10)(x +10)
Step-by-step explanation:
The factorization of the difference of squares is a special form:
a² -b² = (a -b)(a +b)
<h3>Application</h3>
Your expression is recognizable as the difference of squares:
x² -100 = x -10²
Using the above form, the factorization is ...
= (x -10)(x +10) . . . . . . . . matches the second choice
Answer:
hfgdvfhftftfrgrggg equals 2
Step-by-step explanation:
Imagine you have one apple on your left hand. Your friend just gave your another apple. Now, you have two apples. So, the hfgdvfhftftfrgrggg would be 2.
ANSWER
Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
To proof
let us assume that the fluid should be drained and replaced with pure antifreeze be x .
As given
A radiator contains 10 quarts of fluid, 30% of which is antifreeze.
Now write 30% in the decimal form
Now write 60% in the decimal form
After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )
The quantity of antifreeze is
The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
than the equation becomes
solyving
100x +300 - 30x = 600
70x = 300
x = 4.28 quarts (approx)
Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
Therefore the option (c.) is correct .
Well, let's see how it'll effect your grade...
75% ÷ 90% = 0.83
0.83 x 100 = 83%
It would effect your grade by 7 percent, lowering it to 83%
I hope this helps!