I need help with this question please
2 answers:
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Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
9514 1404 393
Answer:
P(0) = 4
P(-2) = 2
Step-by-step explanation:
Put the value where the variable is and do the arithmetic.
P(0) = 2·0³ +3·0² -0 +4
P(0) = 4
__
P(-2) = 2·(-2)³ +3·(-2)² -(-2) +4 = 2(-8) +3(4) +2 +4
P(-2) = -16 +12 +2 +4
P(-2) = 2
