Answer:
Option D :- ![\sf \: 18 {x}^{2} {y}^{2} \sqrt[3]{3 {xy}^{2} }](https://tex.z-dn.net/?f=%20%20%5Csf%20%5C%3A%2018%20%7Bx%7D%5E%7B2%7D%20%20%7By%7D%5E%7B2%7D%20%20%20%20%20%5Csqrt%5B3%5D%7B3%20%7Bxy%7D%5E%7B2%7D%20%7D)
Step-by-step explanation:
![\sf \: 3x\sqrt[3]{648 {x}^{4} {y}^{8} }](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%203x%5Csqrt%5B3%5D%7B648%20%20%7Bx%7D%5E%7B4%7D%20%20%7By%7D%5E%7B8%7D%20%7D)
transform the equation
![\rightarrow \sf \: 3x\sqrt[3]{ {6}^{3} \times {3x}^{2} \times {xy}^{6} \times {y}^{2} }](https://tex.z-dn.net/?f=%20%5Crightarrow%20%5Csf%20%5C%3A%203x%5Csqrt%5B3%5D%7B%20%7B6%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7B3x%7D%5E%7B2%7D%20%20%20%5Ctimes%20%20%20%7Bxy%7D%5E%7B6%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20%7D)
rewrite the expression
![\rightarrow \sf \: 3x \times \sqrt[3]{ {6}^{3}} \times\sqrt[3]{ {3x}^{2}} \times \sqrt[3]{ {xy}^{6} } \times \sqrt[3]{{y}^{2} }](https://tex.z-dn.net/?f=%20%5Crightarrow%20%5Csf%20%5C%3A%203x%20%20%5Ctimes%20%5Csqrt%5B3%5D%7B%20%7B6%7D%5E%7B3%7D%7D%20%20%5Ctimes%5Csqrt%5B3%5D%7B%20%20%7B3x%7D%5E%7B2%7D%7D%20%20%20%5Ctimes%20%5Csqrt%5B3%5D%7B%20%7Bxy%7D%5E%7B6%7D%20%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B%7By%7D%5E%7B2%7D%20%7D)
Simplify the radical expression
![\rightarrow \sf \: 3x \times {6xy}^{2} \sqrt[3]{3xy {}^{2} }](https://tex.z-dn.net/?f=%20%5Crightarrow%20%5Csf%20%5C%3A%203x%20%20%5Ctimes%20%20%7B6xy%7D%5E%7B2%7D%20%5Csqrt%5B3%5D%7B3xy%20%7B%7D%5E%7B2%7D%20%7D)
Multiply
Answer:
f(x) = 2x² + 3
g(x) = x² - 7
( f - g)(x) = 2x² - x² +3 --7
= x² + 3 + 10
= x² + 10
Hope this helps.
The solution to given system of equations is x = 2 and y = -5
<em><u>Solution:</u></em>
<em><u>Given the system of equations are:</u></em>
4x + y = 3 ---------- eqn 1
-2x + 3y = -19 ---------- eqn 2
We have to find the solution to above system of equations
<em><u>We can solve the system by substitution method</u></em>
From eqn 1,
4x + y = 3
Isolate y to one side
y = 3 - 4x ----------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
-2x + 3(3 - 4x) = -19
-2x + 9 - 12x = -19
Combine the like terms
-14x = -19 - 9
-14x = -28
Divide both sides of equation by -14
<h3>x = 2</h3>
<em><u>Substitute x = 2 in eqn 3</u></em>
y = 3 - 4(2)
y = 3 - 8
<h3>y = -5</h3>
Thus the solution is x = 2 and y = -5
You are told 2/9 = 16
Let total number of batteries = x
So you now have 2/9x = 16
To find x divide both sides by 2/9
X = 72 total batteries
Divide b from both sides then it should be a equal C therefore if you add be it be the midpoint of a and C because BNB or equal to a C
