Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
The probability that she gets all 7 questions correct is 0.0078.
Step-by-step explanation:
We are given that Karri takes a 7 question true-false test and guess on every question.
The above situation can be represented through binomial distribution;
where, n = number of samples (trials) taken = 7 question
r = number of success = all 7 questions correct
p = probability of success which in our question is probability that
question is correct, i.e. p = 50%
Let X = <u><em>Number of question that are correct</em></u>
So, X ~ Binom(n = 7, p = 0.50)
Now, the probability that she gets all 7 questions correct is given by = P(X = 7)
P(X = 7) =
=
= <u>0.0078</u>
Answer:
1/2
Step-by-step explanation:
opposite reciprocal
The sum of the left side of these two equations is equal to the same of the right side is these two equations
4x+8y + (-4x+2y) = 20 + 30
10y =50 ( x is eliminated)
y=5
Take this into the second equation
-4x +2y = 30
-4x + 2*5 = 30
x=-5
So x=-5
y=5
Graphing the system of equations is shown in figure attached.
Solution set is (2,-4). The lines will intersect at (2,-4)
Step-by-step explanation:
We need to graph the system of equations.
First we will find value of x and y
Let:
Add eq(1) and eq(2)
Putting value of x in eq(1) and finding y
So, y=-4
Graphing the system of equations is shown in figure attached.
Solution set is (2,-4). The lines will intersect at (2,-4)
Keywords: System of equations
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